Ratio and proportion questions for bank exams: Hello dear students, In this article, we present important questions; on the basis of Ratio and Proportion questions; as well as, Top 100 previously asked questions are available in a PDF,
That you can download using the below Link; therefore, please read this article; throughout the end to get all the information you have come for ;
Ratio and proportion topic is an essential and important part of Mathematics; the majority of Exams often take the questions from Ratio and proportion; such as SSC, Board examination, Banking exams, etc, therefore, our primary concern to let you understand about it, using different examples, so that, you must understand the identity of Ratio & Proportion;
Identity of Ratio questions – Ratios are typically identified on the base of the “Fraction”, for instance- A/B even it is in the form of FRACTION, but in the Ratio form we do write as a:b, where Proportion represents that two Ratios are Equal;
For example- 3/5 is the example of a Ratio, but to understand proportion; we can write this equation as – 9/15= 3/5,
So we check that 9*5 = 45 , and 15*3= 45 , hence 45= 45
Note– This equation relates that the ratio can be written as either in the form of A/B or A: B/ A TO B, while Proportion says that Ratios are equal, where A and B are integers and B is not equal to 0.
Note(2) – A/B or A: B, or A to B, In a type of such expressions, A is the 1st Term ( It is also called antecedent), while B to note as the 2nd term (which we call consequent),
Above example -3/5,(3 is the first term and is antecedent, and 5 is the second term and is denoted consequent ),
Ratio and proportion questions for bank exams easy to moderate level
Understanding the concept of “Ratio and proportion” is of utmost necessary to solve the questions; therefore I will try to make you understand the type of Ratio and Proportion questions from an easy level,
Let’s say an Example – there are 4 boys out of 10 persons, and the remaining number of people represents the number of Girls, so you find that – there are 4 boys and 6 girls, which we can write in Ratio as – 4: 6, 4/6= 2/3, or( 2/5 are boys and 3/5 are Girls ), 2/5*100= 40 % ( No. of Boys,) and 3/5*100= 60 % ( no. of Girls)
This is how we do calculate the ratio, hope you understand that, so let’s move on to another question
Q.1-There are 81 students in class; and, the number of students BOYS and Girls is in the Ratio of 5:4; Then find the number of Girls and Boys respectively?;
Ans– Ratio 5:4 ,where ( number of Boys = 5x ,number of girls= 4x) ,total number of students = 81 , so 5x+4x = 81 , 9x = 81 , x= 81/9 , x= 9 , therefore, number of Boys= 5x = 5*9 = 45 , and The Number of Girls = 4x = 4*9= 36 ,
Q.2 – The Ratio of the Monthly Income of RAM, SOHAN, and SHYAM is 40:50:60; if Ram’s annual income is 200000 rupees; then, find the annual income of Shyam?
Ans– Since annual income and monthly income is discussed; but the monthly incomes are in distinct Ratios, let’s say, Ram, Sohan, and Shyam monthly income is – 40 x,50x,60x,
The annual income of Ram is – 200000; thus the monthly income of Ram – 40 x to his annual income, so we can write – 40 x= 200000/12( 12 is the number of months in a year),
SO X= 200000/12*40 , or X= 416.67; So the monthly income of SHYAM; = 60 * 416.67 = 25000.2 , thus the Annual income of SHYAM will = 25000.2*12= 300002.4
Ratio questions based on Ages & Numbers
Q.3 – The Ratio of the number of Mangoes to that of Oranges was 2:3, but when 2 mangoes and 2 oranges were lost; then the ratio became 3:5, then find the total number of mango and orange.
Ans– Since the former ratio 2:3 of M , and O ,(M= Mango,O =Orange), thus, we can write it as, 2x and 3x, since 2 O & 2 M lost ,thus equation = 2x-2 : 3x-2 , new Ratio became = 3:5 ,
so we can write this equation – 2x-2 /3x-2 = 3/5 , now find the value of X using cross multiplication , so then 10x-10 = 9x -6 , 10x-10-9x-6 = 0, then x-4=0, so x= 4,
Hence the number of Mangoes = 2x ;= 2*4= 8; and Oranges = 3x , 3*4=12 , thus the Total number of Mangoes and Oranges = 8+12 = 20 Ans ,
Q.4- The ratio of the ages of a Father and a SON at present is 7:3 ; 3 years later; the Ratio of the ages of a father and his son will be 5:3; what is the present age ratio of the father and the son?
Ans- 7X:3X , SINCE 3 years later – 7x+3/3x+3 = 5/3, thus eqn- 21x +9 = 15x +15 , 21x-15x= 15-9, 6x=6 , hence X= 1,
Present age Ratio – 7x ,and 3x , 7*1, or 3*1, = 7:3.
Q.5 – the Age of P and Q,7 years ago was 3:4; after 9 years the ratio of their age will 7:8; then find the age of P and Q,
Ans– Former age ratios 3:4 but 7 years ago, so the Equation form – P-7/Q-7= 3/4, THEN 4p-28 =3q-21, so further equation 4p-3q-7=0 (Eqn- 1) , again after 9 years ,their’s age ratio 7:8 , so new equation = p+9/q+9=7/8 , so 8p-7q+9=0 (Eqn-2) ,
Solving Eqn1 &2nd , ( 28p-21q-49 =0 , 24p-21q +27=0) , WE get the value of P = 19 ,and the value of Q =23 , ans ,
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Ratio and proportion questions PDF Download for 100 Questions
This pdf link is available below, moreover, Candidates can also choose another important subject to download the Book in PDF, which that all is only and only for Examination purposes, so here it is, which you can also use,
| Total number of questions” Ratio & proportion questions” | 100 |
| Suitable for | IBPS, RRB, SBI PO, SSC, etc. |
| Total size | 5MB |
| Download Link | Click here |
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